Roots of polynomials

  • #1

Main Question or Discussion Point

I was reading this book - " mathematical methods for physics and engineering"
in it in chapter 1 its says
"F(x) = A(x - α1)(x - α2) · · · (x - αr),"
this makes sense to me but then it also said

We next note that the condition f(αk) = 0 for k = 1, 2, . . . , r, could also be met
if (1.8) were replaced by
F(x) = A(x - α1)^m1(x - α2)^m2 · · · (x - αr)^mr

this confused me...how can you can you just raise each factor to powers m1,m2,...mr etc.How does the function still remain same?
 

Answers and Replies

  • #2
HallsofIvy
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The function doesn't "remain the same" and this doesn't say it does. It just says that the two functions have the same zeros. Both [tex](x- a_r)[/tex] and [tex](x- a_r)^n[/tex] are 0 if and only if [tex]x= a_r[/tex].
 
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