Rope and Bird Mechanics: Calculating the Force on a Hanging Rope

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The discussion focuses on calculating the force exerted by a hanging rope on the ceiling when a bird climbs it with acceleration. The key equation derived is T = mg + M(g + a), where T represents the tension in the rope. Participants debate whether the mass of the rope should vary based on the bird's position, ultimately concluding that the forces acting on the bird include its weight and the reaction force from the rope. A free body diagram is suggested to clarify the forces involved, emphasizing the need to account for both the bird's weight and the tension in the rope. The conversation highlights the importance of understanding the dynamics of forces in this scenario.
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Why anyone is not answering this question...

Homework Statement



a uniform rope of mass m hangs freely from the ceiling. A bird of mass M climbs up the rope with an acceleration A. the force exerted by the rope on the ceiling is

Homework Equations


T = mg + M(g+a) is answer


The Attempt at a Solution


shouldnt we consider M of the rope as a variable here depending upon the position of bird on the rope??
 
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hivipulgoyal! :smile:
vipulgoyal said:
shouldnt we consider M of the rope as a variable here depending upon the position of bird on the rope??

no …

the forces on the bird from the rope must be M(g + a), so that M(g + a) + (-Mg) = Ma

and then the forces on the rope are -mg, -M(g + a) from the bird, and the force from the ceiling :wink:
 
tiny-tim said:
hivipulgoyal! :smile:


no …

the forces on the bird from the rope must be M(g + a), so that M(g + a) + (-Mg) = Ma

and then the forces on the rope are -mg, -M(g + a) from the bird, and the force from the ceiling :wink:

why are we considering the force exerted by the rope on the bird i mean the force M(g+a) is due to gravity and acceleration of the bird
 
vipulgoyal said:
… the force M(g+a) is due to gravity and acceleration of the bird

sorry, but this is nonsense :redface:

the force M(g+a) is the force exerted by the rope on the bird …

it is the force needed to produce a net force of Ma​
 
""the force M(g+a) is the force exerted by the rope on the bird …"""
SORRY BUT THIS IS THE FORCE DUE TO GRAVITY as acc. to you if i jus delete the rope from the equation then there will be no force on the bird and it will be weightless..! does it makes sense...?? not to me at least
 
vipulgoyal said:
""the force M(g+a) is the force exerted by the rope on the bird …"""
SORRY BUT THIS IS THE FORCE DUE TO GRAVITY as acc. to you if i jus delete the rope from the equation then there will be no force on the bird and it will be weightless..! does it makes sense...?? not to me at least

draw a free body diagram for the forces on the bird …

there are exactly two forces, the weight (-Mg) and the reaction force from the rope (R) …

the total force is R - Mg, and this must equal ma …

R - Mg = Ma

or R = M(g + a) :wink:
 
T = mg + M(g+a) is answer
 
vipulgoyal said:
T = mg + M(g+a) is answer

yes, that's for the force on the rope from the ceiling

to find that, you need a free body diagram for the forces on the rope

there are three forces on the rope …

what are they, and how do they add up? :smile:
 
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