Rotational dynamics-rotating door w/ 4 panes

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A rotating door consists of four 90 kg glass panes, and a force of 80 N is applied perpendicularly to one pane at a distance of 1.2 m from the axis of rotation. The correct approach to find the angular acceleration involves calculating the torque, which is the product of the force and the distance from the pivot point. The moment of inertia must be accurately calculated, and the equation net external torque equals moment of inertia times angular acceleration should be properly applied. The initial attempt at calculating angular acceleration was incorrect due to confusion between torque and force. Proper guidance and resources are available for those needing assistance with similar problems.
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Homework Statement



A rotating door is made from four rectangular glass panes, as shown in the drawing. The mass of each pane is 90 kg. A person pushes on the outer edge of one pane with a force of F = 80 N that is directed perpendicular to the pane. Determine the magnitude of the door's angular acceleration.________rad/sec squared. (there is a pic that shows radius 1.2m)


Homework Equations


net external torque=moment of inertia x angular acceleration


The Attempt at a Solution


Tried (90kg*4 panes*1.2m squared) to get moment of inertia=518.40. Then divided 80N b
by 518.40 to solve for angular accel=.1543 This isn't right. Will anyone help?
 
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So the force of 80N is applied at 1.2m from the axis of rotation, correct? For your calculation of Torque/m.o.i., you have used T=80N. Numerically, are you sure about that? Dimensionally, are you sure about that? Look again...
 
Kate Green said:

Homework Statement



A rotating door is made from four rectangular glass panes, as shown in the drawing. The mass of each pane is 90 kg. A person pushes on the outer edge of one pane with a force of F = 80 N that is directed perpendicular to the pane. Determine the magnitude of the door's angular acceleration.________rad/sec squared. (there is a pic that shows radius 1.2m)


Homework Equations


net external torque=moment of inertia x angular acceleration


The Attempt at a Solution


Tried (90kg*4 panes*1.2m squared) to get moment of inertia=518.40. Then divided 80N b
by 518.40 to solve for angular accel=.1543 This isn't right. Will anyone help?


\tau\ = I\alpha}

You have placed force instead of torque in the above equation.
 

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