Rotational Mechanics: Incorrect Statements on Motion of Ball

AI Thread Summary
The discussion centers on the motion of a ball in a rotating disc and evaluates statements about its motion. It concludes that statements claiming the net force is toward the center, that centripetal force is mw^2r, and that the ball's motion is circular are incorrect. Instead, if the ball starts slightly off-center, it must move radially outward due to the absence of centripetal acceleration. The groove's normal force contributes to this outward motion, as it induces a change in direction while the ball accelerates. The conversation emphasizes the importance of understanding the forces acting on the ball in a rotating frame.
vaibhav garg
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1. A ball of mass m is placed in a smooth groove at the centre of disc and the frame starts to rotate with angular speed w, which if the following statement are incorrect?
1) Net force on the ball is towards center.
2) Motion of ball is in radially outward direction w.r.t center.
3) Centripetal force is mw^2r
4) Motion of ball is circular.
The answer to the given question states statements 1, 3 and 4 as incorrect.
2. centripetal force = mw^2r (towards center)3. Shouldn't statement 2 be wrong as the centripetal force acts towards the center and statement 1 be correct.
 

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If answers 1 and 3 are correct, then what is the agent of the force directed towards the centre?
 
PeroK said:
If answers 1 and 3 are correct, then what is the agent of the force directed towards the centre?
I don't know but then again what agent would be there for it to move radially outwards.
 
vaibhav garg said:
I don't know but then again what agent would be there for it to move radially outwards.
also 3 would be wrong anyway because if it moved the radius wold be varying.
 
4
 
vaibhav garg said:
I don't know but then again what agent would be there for it to move radially outwards.

That's quite a good question. If the ball started at the centre of the disc, then there is an argument that it would stay there. But, if it started slighty off-centre, then it can't move in a circle, because there is nothing to give it the necessary centripetal acceleration. It can't move back towards the centre, as that would also require acceleration towards the centre. So, by a process of elimination, it must move radially outwards.

Can you see why this radially outward motion is viable? What is pushing on the ball - and in what direction?
 
PeroK said:
That's quite a good question. If the ball started at the centre of the disc, then there is an argument that it would stay there. But, if it started slighty off-centre, then it can't move in a circle, because there is nothing to give it the necessary centripetal acceleration. It can't move back towards the centre, as that would also require acceleration towards the centre. So, by a process of elimination, it must move radially outwards.

Can you see why this radially outward motion is viable? What is pushing on the ball - and in what direction?
The centrefugal force ?
 
vaibhav garg said:
The centrefugal force ?

The centrifugal force isn't a "what". Something physical must be forcing the ball out.

Note that the ball is not moving directly radially outwards from an external viewpoint: it's curving out in a spiral.
 
PeroK said:
The centrifugal force isn't a "what". Something physical must be forcing the ball out.

Note that the ball is not moving directly radially outwards from an external viewpoint: it's curving out in a spiral.
I can't think of anything...
 
  • #10
vaibhav garg said:
I can't think of anything...

It has to be the groove.
 
  • #11
PeroK said:
It has to be the groove.
but wouldn't the grove be applying the normal force in just the perpendicular direction ?
 
  • #12
vaibhav garg said:
but wouldn't the grove be applying the normal force in just the perpendicular direction ?

Yep! Draw a diagram. The normal force (in the direction of ##\hat{\theta}##) induces outward motion!

Consider this.

a) You have a ball on a string that's fixed to some centre point. You push the ball in the direction of ##\hat{\theta}##, constantly changing the direction of your force to accelerate the ball in a circle. But, the string is necessary to hold the ball in.

b) Without the string, you push the ball, but in addition to accelerating in the ##\hat{\theta}## direction, it also moves away from the centre. That's because ##\hat{\theta}## and ##\hat{r}## are changing direction.

With respect to a fixed origin: An impulse in the ##\hat{\theta}## direction causes motion in that direction, but as the ball moves the direction of motion is no longer only in the ##\hat{\theta}## direction: increasingly, in fact, it becomes motion in the ##\hat{r}## direction.

Try it out!
 
  • #13
PeroK said:
Yep! Draw a diagram. The normal force (in the direction of ##\hat{\theta}##) induces outward motion!

Consider this.

a) You have a ball on a string that's fixed to some centre point. You push the ball in the direction of ##\hat{\theta}##, constantly changing the direction of your force to accelerate the ball in a circle. But, the string is necessary to hold the ball in.

b) Without the string, you push the ball, but in addition to accelerating in the ##\hat{\theta}## direction, it also moves away from the centre. That's because ##\hat{\theta}## and ##\hat{r}## are changing direction.

With respect to a fixed origin: An impulse in the ##\hat{\theta}## direction causes motion in that direction, but as the ball moves the direction of motion is no longer only in the ##\hat{\theta}## direction: increasingly, in fact, it becomes motion in the ##\hat{r}## direction.

Try it out!
Now, I get it. Thanks
 

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