Rotational Motion - Finding Linear Distance

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SUMMARY

The discussion focuses on calculating the linear distance traveled by a point on the edge of a 45.0 cm diameter wheel as it accelerates uniformly from 205 rpm to 385 rpm over 7.5 seconds. The key equations used include angular acceleration (a = (w - v) / t) and the relationship between angular displacement (h) and linear distance (s = r * h). The user initially struggled with the conversion of angular displacement from radians to meters but ultimately resolved the issue independently.

PREREQUISITES
  • Understanding of angular motion concepts
  • Familiarity with unit conversions between rpm and rad/s
  • Knowledge of kinematic equations for rotational motion
  • Basic algebra for solving equations
NEXT STEPS
  • Study the conversion of angular velocity from rpm to rad/s
  • Learn about the relationship between angular and linear motion
  • Explore the implications of uniform acceleration in rotational dynamics
  • Practice solving problems involving angular displacement and linear distance
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Students in physics or engineering courses, educators teaching rotational dynamics, and anyone interested in understanding the principles of angular motion and its applications.

hana.e.kim
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Homework Statement



A 45.0 cm diameter wheel accelerates uniformly from 205 rpm to 385 rpm in 7.5 s. How far will a point on the edge of the wheel have traveled in this time?

Homework Equations



w=omega
v=initial omega
a=angular acceleration
r=radius
h=theta
t=time
s=distance traveled.

w^2=v^2 + 2ah
a=(w-v)/t
h=s/r

The Attempt at a Solution



So, I converted 205 rpm and 385 rpm to rad/s. Then I found angular acceleration by using the formula: a=(w-v)/t. Then I plugged everything into the equation: w^2=v^2 + 2ah and solved for h(theta). Then I converted h(theta), which was in radians, to meters by multiplying it by the radius because h(theta)=s/r. Apparently that's the wrong way though, so if anyone could help me out, I'd love him/her forever. Thank you!
 
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Can you show your calculations? It's much easier to track down an error that way.
 
Actually, I figured out how to do it. Thanks anyway!
 

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