The length of a rectangular swimming pool is twice its width. The pool is surrounded by a cement walk 4 ft wide. If the area of the walk is 748 square feet, determine the dimensions of the pool.(adsbygoogle = window.adsbygoogle || []).push({});

A= the total area bounded by the outer edge of the surrounding walk

W= the area of the walk

P= the area of the pool

x= the length of the short side of the pool

A=P+W

P=x2x=[tex]2x^{2}[/tex]

W=748

A=(x+8)(2x+8)=[tex]2x^{2}+24x+64[/tex]=[tex]2x^{2}+748

[/tex]

solving for x gives x=28.5 feet and 2x=57 feet

The answer sheet says the dimensions are 30 and 60 feet.

Where am I going wrong?

Thanks for any replies.

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# Homework Help: Running by the pool

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