- 67

- 0

A= the total area bounded by the outer edge of the surrounding walk

W= the area of the walk

P= the area of the pool

x= the length of the short side of the pool

A=P+W

P=x2x=[tex]2x^{2}[/tex]

W=748

A=(x+8)(2x+8)=[tex]2x^{2}+24x+64[/tex]=[tex]2x^{2}+748

[/tex]

solving for x gives x=28.5 feet and 2x=57 feet

The answer sheet says the dimensions are 30 and 60 feet.

Where am I going wrong?

Thanks for any replies.