Sakurai page 196: Orbital angular momentum as rotation generator

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From "Modern Quantum Mechanics, revised edition" by J.J. Sakurai, page 196.

Equation (3.6.4),<br /> 1-i \left( \frac{\delta \phi}{\hbar} \right) L_z = 1 - i \left( \frac{\delta \phi}{\hbar} \right) (x p_y - y p_x )<br />Making this act on an arbitrary position eigenket \mid x&#039;, y&#039;, z&#039; \rangle,
Equation (3.6.5),<br /> \begin{eqnarray}<br /> \left[ 1-i \left( \frac{\delta \phi}{\hbar} \right) L_z \right] \mid x&#039;, y&#039;, z&#039; \rangle &amp; = &amp; \left[ 1 - i \left( \frac{p_y}{\hbar} \right) ( \delta \phi x&#039; ) + i \left( \frac{p_x}{\hbar} \right) ( \delta \phi y&#039; ) \right] \mid x&#039;, y&#039;, z&#039; \rangle \\<br /> &amp; = &amp; \mid x&#039; - y&#039; \delta \phi, y&#039; + x \delta \phi, z&#039; \rangle<br /> \end{eqnarray}<br />
What I don't understand is, in equation (3.6.5), why did they operate by the position operators first, and not the momentum operators. Looking at equation (3.6.4), it looks like the ket \mid x&#039;, y&#039;, z&#039; \rangle should be operated on by the momentum operators first.
 
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It wouldn't matter, since [\hat p_{x},\hat y]=[\hat p_{y},\hat x]=0. Remember [\hat p_{i},\hat x_{j}]=i\hbar \delta_{ij}?
 
Oh, OK. Got it. Thanks.
 
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