Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Schrodinger Eqn

  1. Jun 9, 2011 #1
    Hi, I am new to QM, so advanced apologies for the dumb questions to follow. What does "the spectrum of boundstates is non-degenerate" mean? And why is the time-independent Schrodinger eqn reflection invariant? (I'm not sure I quite know what that means either...)

  2. jcsd
  3. Jun 9, 2011 #2


    User Avatar
    Science Advisor

    "Degenerate" energy states are ones which have the same energy. So "the spectrum of bound states is non-degenerate" means no two bound states have the same energy.
    (This is specific to your system though, and not true in general)
    A reflection is a transformation of coordinates x -> -x. So it means that the equation gives the same solutions if you invert the coordinate system.
    (which may also include the _time_ coordinate, since it's time-independent, changing the sign of the time coordinate will by definition not change anything.)
  4. Jun 9, 2011 #3
    Thanks, alxm!
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Schrodinger Eqn
  1. Schrodinger eqn. b.c. (Replies: 0)