Schrodinger Eqn

  1. Hi, I am new to QM, so advanced apologies for the dumb questions to follow. What does "the spectrum of boundstates is non-degenerate" mean? And why is the time-independent Schrodinger eqn reflection invariant? (I'm not sure I quite know what that means either...)

  2. jcsd
  3. alxm

    alxm 1,845
    Science Advisor

    "Degenerate" energy states are ones which have the same energy. So "the spectrum of bound states is non-degenerate" means no two bound states have the same energy.
    (This is specific to your system though, and not true in general)
    A reflection is a transformation of coordinates x -> -x. So it means that the equation gives the same solutions if you invert the coordinate system.
    (which may also include the _time_ coordinate, since it's time-independent, changing the sign of the time coordinate will by definition not change anything.)
  4. Thanks, alxm!
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