- #1
Darren93
- 28
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I'm looking at scintillation detectors and I'm quite confused to the output of the crystal. My notes just say emission output has intensity proportional to input energy. How though? I mean surely for the Photoelectric effect there is a huge spectrum of output energies depending upon shell jumped. If you consider 1 of these energies you would need multiple ionisations to occur to increase intensity output. If multiple are occurring, why? Additionally how can you get mostly PE absorptions at high energy, like ~140kev. Is it say a 140kev photon is absorbed, releasing a 138kev electron? That causes 69 further ionisations. That would make some sense but I'm still confused to what exactly is going on. Plus even with 70 ionisations taking place, if you consider 1 energy output there is only a chance of this occurring. It could be k-alpha, k-beta ect. Are all considered?