- #1
Ki-nana18
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How would you find the second derivative of an implicit function?
y^2-x^2=16
Heres my attempt:
2y(dy/dx)-2x=0
2y(dy/dx)=2x
2y(dy/dx)/2y=2x/2y
dy/dx= x/y
This is only the first derivative. I think I'm suppose to plug in dy/dx back into the original equation. Am I on the right track?
y^2-x^2=16
Heres my attempt:
2y(dy/dx)-2x=0
2y(dy/dx)=2x
2y(dy/dx)/2y=2x/2y
dy/dx= x/y
This is only the first derivative. I think I'm suppose to plug in dy/dx back into the original equation. Am I on the right track?
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