B Semantic question about equilibrium

  • B
  • Thread starter Thread starter etotheipi
  • Start date Start date
  • Tags Tags
    Equilibrium
AI Thread Summary
The discussion centers on the definition of static equilibrium and its application in physics. It questions whether a body experiencing acceleration in one direction but not in an orthogonal direction can be considered in static equilibrium. Participants agree that static equilibrium typically refers to a state of no movement or acceleration in any direction, while acknowledging that conditions can still satisfy equilibrium in a specific direction. The semantic distinction between static equilibrium and general equilibrium conditions is seen as minor, with common sense prevailing in practical applications. Overall, the conversation highlights the nuances of terminology in physics without significant implications for understanding motion.
etotheipi
If a body experiences acceleration in one direction and no acceleration in another (orthogonal) direction, is it accurate to state that the body is in static equilibrium in one direction only? Or is static reserved for strictly no acceleration in any direction? Apologies if this seems pedantic!
 
Last edited by a moderator:
Physics news on Phys.org
I'd go further and say that "static equilibrium" is reserved for things that aren't moving, much less accelerating. Nonetheless, you can certainly apply Newton's law in any direction: if the acceleration in a given direction is zero, the sum of the forces in that direction will be zero. (Kind of an "equilibrium" condition, but I wouldn't call it static.)
 
  • Informative
Likes etotheipi
Doc Al said:
I'd go further and say that "static equilibrium" is reserved for things that aren't moving, much less accelerating. Nonetheless, you can certainly apply Newton's law in any direction: if the acceleration in a given direction is zero, the sum of the forces in that direction will be zero. (Kind of an "equilibrium" condition, but I wouldn't call it static.)

I agree with everything that you say, however if for instance a ball moves across a horizontal surface in some arbitrary motion, when we consider solely the vertical direction we can still write ##y = k##, ##y' = 0## and ##y''=0##, which appears to be precisely the conditions for static equilibrium in this one dimension.
 
What would be the advantage of using the term static equilibrium in that case? (Though I do see your point.)
 
  • Like
Likes etotheipi
Doc Al said:
What would be the advantage of using the term static equilibrium in that case? (Though I do see your point.)

Now that I think about it, probably none at all! To me it just seems like a succinct way of stating that there is neither velocity nor acceleration in a particular direction, which is slightly more constrained than just no acceleration.

In practice, the semantic distinction is probably not so important (i.e. common sense prevails), as you suggest!
 
Last edited by a moderator:
etotheipi said:
To me it just seems like a succinct way of stating that there is neither velocity nor acceleration in a particular direction, which is slightly more constrained than just no acceleration.

Are you thinking of only two spatial directions? If so, the term used for that is rectilinear motion.

Note that in general, any motion confined to a plane would have zero velocity and zero acceleration in the direction perpendicular to that plane.
 
  • Informative
Likes etotheipi
Thread 'Question about pressure of a liquid'
I am looking at pressure in liquids and I am testing my idea. The vertical tube is 100m, the contraption is filled with water. The vertical tube is very thin(maybe 1mm^2 cross section). The area of the base is ~100m^2. Will he top half be launched in the air if suddenly it cracked?- assuming its light enough. I want to test my idea that if I had a thin long ruber tube that I lifted up, then the pressure at "red lines" will be high and that the $force = pressure * area$ would be massive...
I feel it should be solvable we just need to find a perfect pattern, and there will be a general pattern since the forces acting are based on a single function, so..... you can't actually say it is unsolvable right? Cause imaging 3 bodies actually existed somwhere in this universe then nature isn't gonna wait till we predict it! And yea I have checked in many places that tiny changes cause large changes so it becomes chaos........ but still I just can't accept that it is impossible to solve...

Similar threads

Back
Top