Finding the Constant in a Separable Differential Equation

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Homework Statement


\frac{dy}{dx} = \frac{1+\sqrt{x-2}}{1+2y}

I have solved the equation down too

y + y2 = x + (2/3)(x-2)(3/2) + C1


I am not sure where to go from here... Do I solve for C1 and then plug it back into the equation and solve it as a quadratic or just solve it as a quadratic?
 
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If you have an initial condition, you can use it to solve for C whenever you want. Otherwise there's no way of determining its value.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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