Seperable Partial Differential Equation

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SUMMARY

The discussion centers on solving the separable partial differential equation given by u_{x} = u_{y} + u. The method of separation of variables is employed, leading to the equation \frac{X'}{X} = \frac{Y'}{Y} + 1. The user queries whether the constant term '1' affects the use of \lambda^{2} in their solution breakdown, which includes three cases: Case 1 with \lambda^{2} = 0, Case 2 with \lambda^{2} = -\lambda^{2}, and Case 3 with \lambda^{2} = \lambda^{2}. The discussion highlights the nuances of applying characteristics in first-order PDEs.

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Homework Statement



u_{x}=u_{y}+u

Homework Equations



Separation of variables

The Attempt at a Solution



It reduces to \frac{X'}{X}=\frac{Y'}{Y}+1

My question is does the 1 change at all how I use \lambda^{2}? In other words, will my solution still break down into this:

Case 1: \lambda^{2}=0

\frac{X'}{X}=0 and \frac{Y'}{Y}+1=0

Case 2: -\lambda^{2}

\frac{X'}{X}=-\lambda^{2} and \frac{Y'}{Y}+1=-\lambda^{2}

Case 3: \lambda^{2}

\frac{X'}{X}=\lambda^{2} and \frac{Y'}{Y}+1=\lambda^{2}
 
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This is correct although normally for first order PDEs, we use the method of characteristics.
 

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