Seperating metals in a solution

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To separate silver, barium, and iron (III) ions from a solution, anions corresponding to their charges should be added to form precipitates. Adding OH^- will precipitate silver, CO3^2- will precipitate barium, and PO4^3- will precipitate iron (III). This method effectively isolates each metal ion based on their solubility products. It's important to focus on solubility rather than oxidation states during this process. The proposed procedure is valid for achieving the desired separation of metal ions.
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A solution is found to have varying quantities of silver, barium and iron (III) ions.

Suggest a procedure for seperating the ions by precipitation.


Ok ...silver is +1, barium is +2, and iron (III) is +3... so I would have to add anions of the same value (but negative) to the solution in order to form precipitates.

so for example i could add OH^- and it would form a precipitate with the silver.

I could add CO3^2- and it would form a precipitate with the barium.

And I could add PO4^3- and it would form a precipitate with the iron (III) ions.

This procedure would separate all the metal ions.

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This is right... right? :smile:
 
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anyone?

I'm pretty sure I'm rigght.. but just want to make sure.

thanks
 
Think in terms of solubility products, not oxidation states.
 
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