Finding Volume Using Triple Integrals: A Brief Guide

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To find the volume between the function z=4-x^2-y^2 and the x/y plane, the correct integrand is 4-x^2-y^2. The suggested limits of integration need clarification, as the bounds should be defined correctly for x, y, and z. Converting to polar coordinates simplifies the integration, where z=4-r^2 applies. The volume can be calculated by integrating in the first quadrant and multiplying the result by four for symmetry. Understanding the values for the angle θ_0 and the radius r_m is crucial for completing the integration.
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Homework Statement



i have to find the volume between the function z=4-x^2-y^2 and the x/y plane

The Attempt at a Solution



I think I should be fine with the limits of integration but am not 100% confident what I am integrating.

is it 4-x^2-y^2-z??

or 4-x^2-y^2?
 
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So I'm just going to integrate dv I think this might be correct. my bounds would be x=0->sqrt(y^2-4) then y=0->sqrt(z-4) then z=0->4. And then I would integrate in this order. Is this correct?
 
Why not convert to polar coordinates? Then z=4-r^2 right? I assume you mean positive z, the paraboloid above the x-y plane. It's symmetrical so you could just integrate in the first quadrant and multiply by four:

V=4\int_0^{\theta_0}\int_0^{r_m} (4-r^2)rdrd\theta

Can you understand how I did that and come up with the values for \theta_0 and r_m?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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