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Ideal transformer problem, angular frequency w

  1. Jul 10, 2010 #1
    Hello,

    I have some doubts in the following problem of a transformer, specially on parts 2 and 4.
    I would be very grateful if someone could please give me any ideas specially about those parts...

    1. The problem statement, all variables and given/known data

    15g8sap.png

    3. The attempt at a solution

    1)

    Applying KVL in each mesh:
    Mesh 1: V1 = jwL1I1 - jwMI2
    Mesh 2: V2 = jwMI1 - jwL2I2

    2)

    power for RL?

    First, apply KVL in each mesh:

    Mesh 1 : V1 = jwL1I1 - jwMI2
    Mesh 2 : 0 = jwMI1 - (jwL2 + RL) I2

    get I2, and substitute it in the power function below:

    P = V I2 = RL I2^2

    Regarding M, I only know the formula of M = k sqrt(L1 L2).
    I wonder if there is another way to get M....Any ideas ?

    3) Z1?

    V1 = Z1 I1
    Z1 = V1 / I1

    First, apply KVL in each mesh:

    Mesh 1 : V1 = jwL1I1 - jwMI2
    Mesh 2 : 0 = jwMI1 - (jwL2 + jwL) I2

    get I2 from equation of Mesh 2, and substitute it in Mesh 1 equation.
    After that, substitute V1 from Mesh 1 equation into the equation below:

    Z1 = V1 / I2 =

    So the result is:

    Z1 = jwL1 + (w^2 M^2)/(jwL2 + jwL)

    4) w?
    I have absolutely no idea on how to do this part.
    V and I in phase means : V = Vm cos(wt + 0), I = Im cos(wt + 0)
    and an ideal trasnformer means that k =1 from the equation for M...
    Any ideas for this part?

    Thanks in advance!
     
  2. jcsd
  3. Jul 12, 2010 #2

    berkeman

    User Avatar

    Staff: Mentor

    Hint on #4 -- What is the relationship between I and V at RLC resonance?
     
  4. Jul 12, 2010 #3
    Thank you very much for your reply.

    After looking at a physics book, I undestood that:

    1) at resonance, source voltage and current are in phase, which means:
    V = Vm cos(wt + 0), I = Im cos(wt + 0)

    2) at resonance, we can do: imaginary part of Zin (input impedance) = 0

    since the problem meets 1) we do the following:

    input impedance: Zin = R + j(wL + 1/wC)
    Applying 2) : Im(Zin)=wL + 1/wC = 0
    And extract w from the above equation...

    The problem now is, I think that the above steps are for a simple RLC circuit, what would happen to a transfomer ?
     
    Last edited: Jul 12, 2010
  5. Jul 13, 2010 #4
    Ok, I realized how to get the the input impedance for this part of the problem.

    The input impedance must be Zin = Zn + Zp where:
    Zn is the equivalent impedance of Resistance + Capacitor (R + 1/jwC)
    Zp is a the equivalent impedance of the mutually coupled coils + coil L (as calculated in part 3 of the problem, but must re-calculate again since the polarities -dots- haven been changed)

    Does this sound right?
     
  6. Jul 13, 2010 #5

    berkeman

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    Staff: Mentor

    You're on the right track. However, my initial guess is that the polarity dot reversal thing doesn't make any difference. The whole secondary is floating (no connections to the primary side), so I don't think the polarity makes any difference. The turns ratio, however, does come into the calculations...
     
  7. Jul 18, 2010 #6
    Thanks for your reply.

    I have tried this part again and, as you said, the polarity change does not seem to make any difference in this part...

    Steps:
    (supposing I1 I2 as the currents for meshes 1 and 2)

    Z1 = V1 / I1

    KVL mesh 1: V1 = kwL1I1 + RI1 + I1/jwC + jwMI2

    KVL mesh 2: jwMI1 + jwL2I2 + jwLI2 = 0

    After some algebra, we get Z1 = R + jwL1 + 1/jwC + (w^2M^2)/(jwL2 + jwL)

    In resonance, impedance is purely resistive so imaginary part is 0:

    wL1 - 1/wC - (wM^2)/(L2 + L) = 0

    After some manipulation I finally got: [tex]w = \frac{1}{\sqrt{C(L1-\frac{M^2}{L2+L})}}[/tex]

    Would it be right now?

    Thanks.

    (I think we could have also thought part 4 as an extension of part 3 where a resistor and capacitor have been added in series, whithout doing all the recalculation again, however I wanted to check the impact of the polarity change)
     
  8. Jul 19, 2010 #7

    berkeman

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    Staff: Mentor

    I don't think L1 or L2 should show up in the solution. If the transformer is doing its job, L1 and L2 just transform the load impedance L across the transformer by the square of the turns ratio. You can get the turns ratio from the ratio of L1 to L2.
     
  9. Jul 19, 2010 #8
    Thanks for your reply but I think I don't understand it very well...

    1) Why is my solution wrong ? Why L1 or L2 should not show up in the solution? I have a textbook where input impedance is calculated as I did...(impedance circuit 1 + reflected impedance from circuit 2)

    2) Ideal transformer, Turns ratio N = N2/N2, V2/V1 = N2/N1 = I1/I2

    According to Wikipedia: Ideal Transformer: The impedance in one circuit is transformed by the square of the turns ratio, For example, if an impedance ZL is attached across the terminals of the secondary coil, it appears to the primary circuit to have an impedance of ZL(N1/N2)^2. This relationship is reciprocal, so that the impedance ZL of the primary circuit appears to the secondary to be ZL(N2/N1)^2.

    So... the impedance of the first circuit should be... Z1 = R + jwL1 + 1/jwC + jwL(N1/N2)^2 ?
    The solution should be expressed in terms of N1 and N2?

    I am sorry but is the first time I am studying this and everything sounds quite confusing...

    Thanks again!
     
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