Setting up triple integral in cylindrical coords (looking to check my answer)

[a1010711]

Homework Statement

set up an integral in cylindrical coords to compute the volume of the solid S bounded by the sphere x^2+y^2+z^2=12 and the cone 3z^2=x^2+y^2 where z>=0

The Attempt at a Solution

i will post my answer here. please let 'I' stand for integral:

i get,

I[0,2pi] , I[0,3] I[r/sqrt[3],sqrt[12-r^2] r dz dr dtheta.



so theta goes from 0 to 2pi
r goes from 0 to 3 etc

thank you

 

[Dick]

It says to find volume. So the function you are integrating is '1'. That's a little hard to read, but it looks ok to me.