Understanding Shear Stress Theories: Moors Circle & McGraw Hill

Click For Summary
SUMMARY

This discussion focuses on the application of Mohr's Circle in determining shear stress, specifically addressing discrepancies between McGraw Hill Connect solutions and provided course materials. The maximum principal stress (sigma1) is confirmed as 350 MPa, aligning with the yield strength (Sy). The maximum shear stress is calculated using the formula n = Sy/Tmax, where Tmax is half of Sy, resulting in a shear stress of 175 MPa. The discussion highlights the importance of understanding the relationship between principal stresses and shear stress in engineering contexts.

PREREQUISITES
  • Understanding of Mohr's Circle for stress analysis
  • Familiarity with yield strength (Sy) concepts
  • Knowledge of principal stresses in three-dimensional stress states
  • Basic proficiency in using McGraw Hill Connect for engineering assignments
NEXT STEPS
  • Research the derivation and applications of Mohr's Circle in stress analysis
  • Study the relationship between principal stresses and shear stress in materials
  • Explore advanced topics in material yield strength and failure theories
  • Learn how to effectively use McGraw Hill Connect for engineering problem-solving
USEFUL FOR

Engineering students, materials scientists, and professionals involved in structural analysis and design will benefit from this discussion, particularly those focusing on shear stress calculations and the application of Mohr's Circle in real-world scenarios.

LT72884
Messages
335
Reaction score
49
Homework Statement
A ductile hot-rolled steel bar has a minimum yield strength in tension and compression of 350 MPa. Using the distortion-energy and maximum-shear-stress theories, determine the factors of safety for the following plane stress states.

σx = 100 MPa and σy = 100 MPa
Relevant Equations
NA
Hello:)
Our homework is done through mcgraw hill connect. I am able to see the solution to the problem and it contradicts what the book and powerpoint says.

according to the powerpoint given by my professor, moors circle, sigma1 = Sy or yield strength. Powerpoint also states that sigma(x) is sigma1, sigma(y) is sigma2 and sigma(z) is sigma3.

If the powerpoint is correct, then there is no way that sigma(x) from the mcgraw hill assignment IS 100, because Sy is 350. The solution states sy is 350 as well. see attached file

n=sy/Tmax

Tmax we know is half of sy based on moors circle so 350/175 = n

view attached files to see what i mean
 

Attachments

  • moors circle.PNG
    moors circle.PNG
    5.2 KB · Views: 194
  • msst.PNG
    msst.PNG
    6.5 KB · Views: 212
Physics news on Phys.org
Based on the Mohr's circle, if the maximum principal stress is 350 Mpa and the other principal stresses are 0 MPa, what is the maximum shear stress?

If the three principal stresses are 100 MPa, 100 MPa, and 0 MPa, what is the maximum shear stress?
 

Similar threads

Replies
6
Views
4K
  • · Replies 1 ·
Replies
1
Views
12K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 3 ·
Replies
3
Views
9K
Replies
11
Views
4K
  • · Replies 18 ·
Replies
18
Views
8K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
Replies
6
Views
14K