Following Griffiths derivation on pg 44 of the eigen-states of SHO Hamiltonian, he says that we can now find all eigenvalues, but doesnt say how he knows that a and a dagger will indeed take you between nearest neighboring orthogonal states.(adsbygoogle = window.adsbygoogle || []).push({});

in other words, how do we know the ladder operators does raise us by quanta of energy,

or equivalently, how do we know that hbar omega is the smallest quanta of energy give the SHO Hamiltonian ?

Thank you :)

Aim For Clarity

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# SHO Ladder Method missed states?

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