Short question about integrals

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integral identity

if we have [tex]\int dt f(t) = \int dt g(t)[/tex] where both integrals are indefinite integrals, can we immediately conclude that f(t) = g(t) ? I know this doesn't work with definite integrals.
 
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If the two integrals are equivalent, then this implies to me at every t the shapes of f(t) and g(t) are equivalent. It does not work with definite integrals because it's entirely possible for two functions to have the same integral over a certain interval but have entirely different shapes.
 
Write it out in complete for example:

[tex]\int^xdt\;f(t) = \int^x dt\;g(t).[/tex]

In other words, write the indefinite integrals as definite integrals. Now apply the fundamental theorem of calculus and you will find out that yes, indeed, f = g.

Carl