Show for tensors (A · B) : C = A^T · C : B = C · B^T : A

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SUMMARY

The discussion focuses on proving the identities involving tensors using Einstein notation: (A · B) : C = A^T · C : B = C · B^T : A. The user initially struggled with converting the double inner product into a summation format but successfully resolved the issue. The key transformation involved recognizing that (A · B) : C can be expressed as D_{ik} C_{ik}, where D_{ik} is derived from the product A_{ij} · B_{jk}. This simplification led to a clearer understanding of the tensor relationships.

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Homework Statement


using Einstein notation, show the following identities are true

(A · B) : C = A^T · C : B = C · B^T : A



Homework Equations





The Attempt at a Solution


(A · B) : C=(A_{ij} · B_{jk} ) : C
= D_{ik} C_{ik}
= C_{ik} D_{ik}
= C_{ik} (A_{ij} · B_{jk} )

That's as far as I can get. No clue as what to do next, any pointers would be
greatly appreciated :)
 
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Bjk = BTkj
 
Thanks for the response :)
I got it solved since then, I had trouble trying to convert the double inner product as
a summation. Once I figured that out, it was as easy as pie
 

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