Show how to determine the domain of each of the following functions

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To determine the domain of the functions f(x) = ln(1 - ln(x)), g(x) = (x^2 - 1)/(x^4・e^(2x) - 2x^2・e^(2x) - 8e^(2x)), and h(x) = sqrt(6 - e^(-5t)), specific conditions must be met. For f(x), the argument of the natural logarithm must be positive, requiring 1 - ln(x) > 0, which leads to x > e. For g(x), the denominator cannot equal zero, necessitating the solution of x^4・e^(2x) - 2x^2・e^(2x) - 8e^(2x) = 0 to find excluded values. For h(x), the expression under the square root must be non-negative, meaning 6 - e^(-5t) ≥ 0, which constrains t to be greater than or equal to a certain value. Understanding these conditions is essential for identifying the domains of the given functions.
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Homework Statement



Show how to determine the domain of each of the following functions:
a) f(x) = ln(1 - ln(x))
b) g(x)=(x^2 -1)/(x^4・e^2x - 2x^2・e^2x - 8e^2x)
c) h(x)= sqrt(6-e^-5t)
Can somebody show me how to do these questions?

Homework Equations





The Attempt at a Solution


I have no idea...Can somebody show me how to do these questions?
 
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Could you possibly try looking at the graphs?:wink:
 
Kazane said:

Homework Statement



Show how to determine the domain of each of the following functions:
a) f(x) = ln(1 - ln(x))
What is the domain of ln(x)? For what x is 1- ln(x) in that set?

b) g(x)=(x^2 -1)/(x^4・e^2x - 2x^2・e^2x - 8e^2x)
You can not divide by 0. Set the denominator equal to 0 and solve for x. Whatever x you get is not in the domain.

c) h(x)= sqrt(6-e^-5t)
You cannot take the sqrt of a negative number (asssuming that these are real valued functions). For what t is 6- e^(5t) negative?

Can somebody show me how to do these questions?

Homework Equations


The Attempt at a Solution


I have no idea...Can somebody show me how to do these questions?
 
Thank you very much!
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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