Show That a Function is Contractive?

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SUMMARY

The function abs(x)^(2/3) is analyzed for contractiveness on the interval where abs(x) ≤ 1/3. A function is contractive if there exists a constant λ < 1 such that abs(F(x) - F(y)) ≤ λ * abs(x - y) for all x and y in the domain. The discussion concludes that no such λ exists for this function, particularly as the interval approaches zero, where the limit of the ratio |F(x) - F(y)|/|x - y| approaches infinity, indicating non-contractiveness.

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Homework Statement


Show that the following function is contractive on the indicated intervals. Determine the best values of [lamda] in Equation (2).

abs(x)^(2/3) on abs(x) < or = 1/3


Homework Equations


A mapping (or function) F is said to be contractive if there exists a number [lamda] less than 1 such that:

(Equation (2))
abs(F(x)-F(y)) < or = [lamda]*abs(x-y)

for all points x and y in the domain F.

The Attempt at a Solution


I'm not really sure what to do with this one or how to get [lamda] in this case.
 
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mean value theorem?

it seems that for the function that is given, such lamda doesn't exist. consider a interval extremely close to 0, let's say
(-\epsilon, \epsilon)

you see that
\frac{|F(x)-F(y)|}{|x-y|}
goes to infinity, as it approaches the derivative at 0.

are you sure you have the correct question?
 
Thanks for responding, tim_lou. Yes, I'm sure I have the correct question. :) Maybe it's a trick question and it's actually not contractive?
 

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