Show that Q_F is not a division ring.

Click For Summary
SUMMARY

The discussion centers on proving that the quaternionic ring Q_F, defined as Q_F={a_1+a_i i+a_j j+a_k k|a_1,a_i,a_j,a_k ∈ F} where F is a finite field of characteristic p∈{2,3,5}, is not a division ring. Key calculations show that for elements α=1+i and β=1+i+j, the product αβ results in zero when p=2, indicating the presence of zero divisors. The inability to find multiplicative inverses for certain elements under these characteristics confirms that Q_F does not satisfy the criteria for being a division ring.

PREREQUISITES
  • Understanding of finite fields, specifically characteristics p=2, 3, and 5.
  • Familiarity with quaternion algebra and its properties.
  • Knowledge of ring theory, particularly the definitions of division rings and zero divisors.
  • Proficiency in mathematical notation and LaTeX for clear problem presentation.
NEXT STEPS
  • Study the properties of quaternion rings over finite fields.
  • Research the relationship between zero divisors and division rings in ring theory.
  • Learn how to effectively use LaTeX for mathematical expressions and proofs.
  • Explore examples of non-division rings to understand their characteristics and structure.
USEFUL FOR

This discussion is beneficial for mathematicians, students studying abstract algebra, and anyone interested in the properties of quaternionic rings and their implications in ring theory.

HaLAA
Messages
85
Reaction score
0

Homework Statement


Let F be a finite field of characteristic p∈{2,3,5}. Consider the quaternionic ring, Q_F={a_1+a_i i+a_j j+a_k k|a_1,a_i,a_j,a_k ∈ F}. Prove that Q_F is not a division ring.

Homework Equations

The Attempt at a Solution


Let α=1+i,β=1+i+j∈QF. Then

αβ=(1+i)(1+i+j)=(1−1)+(1+1)i+(1+1)j+(1−1)k=2i+2jWith characteristic p=2, αβ=0.

With characteristic p=3, αβ=2(i+j).

With characteristic p=5, αβ=3(i+j).
As I keep working with the method I have the following:αγ=(1+i)(i+2j)=(−1)+(1)i+(2)j+(2)k=−1+i+2j+2kp=2, αγ=1+i. p=3, αγ=2+i+2j+2k. p=5, αγ=4+i+2j+2k.βγ=(1+i+j)(i+2j)=(−1−2)+(1)i+(2)j+(2−1)k=−3+i+2j+kp=2, βγ=1+i+k. p=3, βγ=i+2j+k. p=5, βγ=2+i+2j+k.

I don't get any zero divisors, I may make some error somewhere because I should get zero divisors when p=3,5 also.
 
Physics news on Phys.org
A division ring is a ring in which every non-zero element has a multiplicative inverse. So to prove that a ring is not a division ring, you need to find an element that has no multiplicative inverse.

The manipulations you have done seem to be related to a different question, which is whether the ring has any zero divisors. Do you have a theorem that says the two questions are related?

You are likely to receive more help if you use LaTeX to present the problem clearly. The first line that defines Q_F is too hard to decipher in the format you have used.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K