Show that this system is not a vector space

  • #1
charmedbeauty
271
0

Homework Statement



Show that the system S is not a vector space by showing one of the axioms is not satisfied with the usual rules for addition and multiplication by a scalar in ℝ3

S={x(ℝ3):2x1+3x32-4x23=0}


Homework Equations





The Attempt at a Solution



The subscripts for the x's are strange I think but I guess that shouldn't make a difference.

But I'm really stuck on this I think it should be fairly easy though.

but for example if I try closure under scalar multiplication

or closure under addition I keep coming to a dead end because I don't know the value of the x's.

ie λ[2x1+3x32-4x23]=λ[0]

...λ[2x1+3x32-4x23]=0

I think I just need a hint in the right direction. Thanks
 

Answers and Replies

  • #2
HallsofIvy
Science Advisor
Homework Helper
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The way I see it, you have one major problem- what you are trying to prove is not true!

Now, please tell us the exact wording of the problem. I suspect you are misstating it.
 
  • #3
36,432
8,410

Homework Statement



Show that the system S is not a vector space by showing one of the axioms is not satisfied with the usual rules for addition and multiplication by a scalar in ℝ3

S={x(ℝ3):2x1+3x32-4x23=0}

I don't understand what you have above. Presumably x is a vector in R3. Why are there two subscripts on some of the variables in your equation?
 
  • #4
charmedbeauty
271
0
The way I see it, you have one major problem- what you are trying to prove is not true!

Now, please tell us the exact wording of the problem. I suspect you are misstating it.

I don't understand what you have above. Presumably x is a vector in R3. Why are there two subscripts on some of the variables in your equation?

Ok sorry I did mistake the problem.

it really should have said 2x1+3x32-4x32

I mistakenly read it as it was not typed out ver well and it appeared to look like weird subscript notation.

and I solved it no problems

Thanks for letting me know!
 

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