Show that x(t) approaches infinity in finite time

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Homework Statement



Consider the equation \dot{x} = rx + x^3, where r>0 is fixed. Show that x(t) \rightarrow \pm \infty in finite time, starting from any initial condition x_{0} \neq 0.

Homework Equations



I can think of none.

The Attempt at a Solution



The idea alone of x(t) approaching infinity in "finite time" throws me for a loop. Does this merely mean that |x(t)| becomes very large very quickly? That it is increasing (x > 0) or decreasing (x < 0) increasingly quickly as it "moves away from the origin"? It strikes me as impossible for something to "become infinite" in a finite amount of time. This is from Strogatz' "Nonlinear Dynamics and Chaos", Exercise 2.5.3 if you are interested.

Thank you!
 
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Solve the equation! You have:
<br /> \frac{1}{x(r+x^{2})}\frac{dx}{dt}=1<br />
Use partial fractions to separate to get:
<br /> \frac{1}{x(r+x^{2})}=\frac{1}{rx}-\frac{1}{r(r+x^{2})}<br />
And then simply integrate, this will give the answer.
 
I would assume the phrase "approaches infinity in finite time" means the graph has an asymptote.
 
Indeed. There is a vertical asymptote as a certain finite value of t.
 
I think I now understand the math behind this, although I'm unable to come up with a physical situation that models it?
 
First off, can you do the integral?
<br /> \frac{1}{r}\int \frac{1}{x}-\frac{1}{r+x^{2}}dx=\int 1dt<br />
Physically this would represent a shock wave of some kind.
 
We end up with: \frac{ln(x) - (\arctan(x/\sqrt{r})/\sqrt{r})}{4} = t. So if this is a shockwave, what exactly is x(t) modeling? Surely not position?

Sorry for what I can kind of tell are pretty basic questions. I've had very little experience with differential equations so I'm sort of learning as I go along in Strogatz.
 
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You also have a constant of integration in there somewhere which you can calculate.

x would represent something like the gradient of the wave at a given time.

So what values on the RHS would make it infinite? look at both the log and arctan terms.
 
Are you sure about that partial fraction simplification? I get
\frac{1}{rx} - \frac{x}{r(r+x^2)}
 
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I think you could be right there...
 
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