- #1

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## Homework Statement

## The Attempt at a Solution

it does not exist, but i cant get different limits, im only getting it approaches 0

i replaced x=1 only, y=0 only, y=x, x=y but i'm only getting 0 as my limit.

thanks

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- Thread starter vantz
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- #1

- 13

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it does not exist, but i cant get different limits, im only getting it approaches 0

i replaced x=1 only, y=0 only, y=x, x=y but i'm only getting 0 as my limit.

thanks

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- #2

mathwonk

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this one is very familiar, and is done by letting x=y.

- #3

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im still approaching 0 when x=y

- #4

gb7nash

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im still approaching 0 when x=y

You shouldn't be. Replacing y with x:

[tex]\lim_{(x,y) \to (0,0)} \frac{x*x}{x^2+x^2} = ...[/tex]

- #5

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oh so first i rewrite the limit into a more familiar one and then solve. but i don't see how they are related.

edit:nvm i got it.

edit:nvm i got it.

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- #6

SammyS

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Yes, if you let x=1, and take the limit of the result as y→0, the limit is zero.## Homework Statement

## The Attempt at a Solution

it does not exist, but i cant get different limits, im only getting it approaches 0

i replaced x=1 only, y=0 only, y=x, x=y but i'm only getting 0 as my limit.

thanks

Similarly, letting y=0 and taking the limit of the result as x→1, also gives zero.

Use these results along with the limit obtained as others have suggested. What's your final conclusion?

- #7

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Yes, if you let x=1, and take the limit of the result as y→0, the limit is zero.

Similarly, letting y=0 and taking the limit of the result as x→1, also gives zero.

Use these results along with the limit obtained as others have suggested. What's your final conclusion?

i showed the relation between the original limit and [xy]/(x^2+y^2) as (x,y)-->(0,0).

numerator factorizes to y(x-1), then i replaced (x-1) with t, and as x→1, t→0. new limit does not exist because it approaches 1/2 and 0.

- #8

SammyS

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Correct !

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