Showing work (Perfectly Elastic Collision)

AI Thread Summary
In a perfectly elastic collision between two pool balls with equal mass, one ball traveling west at 2.0 m/s and the other east at 5.0 m/s will exchange velocities post-collision. The confusion arises from understanding how to show the work for the calculations involved. The key equations for momentum and kinetic energy conservation should be applied to solve the problem. Clarifying the specific requirements of the homework question is crucial for providing accurate assistance. The discussion highlights the need for a complete problem statement to facilitate effective problem-solving.
madmax2006
Messages
7
Reaction score
0

Homework Statement



Two pool balls hit head on. V(1) = 2.0 m/s west, V(2) = 5 m/s east. Mass is the same for each ball.

Homework Equations



7901fde5f0d74ca583013c3f86135133.png


The Attempt at a Solution



m(1)*(-2m/s)^2 + m(2)*(5m/s)^2 =? no idea...I just know that each ball should be going the same speed and direction as the other.

I'm totally confused as to how I show work.

Thank you for reading the probably & attempting to help even if you're not able to. I'm open eyes & ears to everyone.
 
Physics news on Phys.org
Hi madmax2006, welcome to PF.
You have not written the problem completely. what is required in the problem?
 
Got it, thanks anyways! :)
 
Last edited:
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanged mass'

Thread 'A cylinder connected to a hanged mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Speed of charged balls after collision
Replies
13
Views
1K
Solving Elastic Collision of Two Balls: Theory & Solutions
Replies
15
Views
3K
Kinetic energy and momentum in an elastic collision
Replies
22
Views
3K
Solving the Elastric 3-Body Collision Problem
Replies
2
Views
2K
MIT OCW 8.01 PS11.3: Elastic Collision Between Ball and Pivoted Rod
Replies
10
Views
2K
Elastic collision of block on block
Replies
4
Views
2K
Work done during a collision -- Change in Kinetic Energy & change in Momentum
Replies
1
Views
2K
Elastic collision with pendulum
Replies
4
Views
5K
Elastic Collision in two dimensions question
Replies
6
Views
2K
Elastic Collision and Momentum of Ice Skaters
Replies
16
Views
3K

Hot Threads

Recent Insights

Back
Top