Signal average power (complex signal)

Click For Summary
SUMMARY

The discussion centers on evaluating the average signal power of the complex signal x(t) = e ^ jwt. The participant questions the necessity of taking the magnitude of the complex signal in the integral and the real-world implications of complex signals. They attempted to evaluate the integral of e ^ jwt using two methods: first by expressing it in terms of cosine and sine, and second by squaring the function to yield e ^ j 2wt. The results of these methods produced different integral values, prompting further inquiry into the mathematical validity of their approach.

PREREQUISITES
  • Complex signal analysis
  • Integral calculus
  • Euler's formula
  • Trigonometric identities
NEXT STEPS
  • Study the properties of complex exponentials in signal processing
  • Learn about the significance of magnitude in complex signal power calculations
  • Explore the relationship between complex signals and real-world applications
  • Investigate the differences in integral evaluation techniques for complex functions
USEFUL FOR

Students and professionals in electrical engineering, signal processing, and applied mathematics who are working with complex signals and their power evaluations.

O.J.
Messages
198
Reaction score
0

Homework Statement



Evaluate the average signal power of the complex signal x(t) = e ^ jwt

Homework Equations


The Attempt at a Solution



I know how to solve this but I have a couple of questions on why we have the take the magnitude of the complex signal in the integral? Besides, does a complex signal mean anything in reality? because the way I figured it is complex analysis is just a mathematical tool to help us analyse sinusoidal signals and a signal is always a real or an imaginery part of a complex function (e ^ jwt) and can't be both.

And as such I tried evaluating the integral of e ^ jwt from 0 to To using two ways:

1. write the exponential e ^ jwt in terms of cos and j sin then square that to give cos^2 wt +j2cos (wt) sin (wt) - sin^2 wt where it evaluates to some finite value
2. square the funciton so it becomes e ^ j 2wt and write that in terms of cos and j sin where it evaluates to 0

this is too mathematical I know, but how come the two mathematically valid manipulations yield integrals with different values?
 
Physics news on Phys.org
y am i being ignored?
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
11K
Replies
7
Views
6K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
1
Views
2K
  • · Replies 26 ·
Replies
26
Views
6K