Signal to Noise Ratio: Questions for my multimedia and signals class

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SUMMARY

The discussion focuses on calculating the Signal to Noise Ratio (SNR) for the signal defined by x[n] = 5sin(0.22*pi) in a system with a known noise RMS value of 0.5. The relevant equations include RMS = A/root(2), SNR = (Asignal/Anoise)^2, and SNRdB = 10log10(SNR). The amplitude A for the noise is determined to be root(2)/2, while the amplitude for the signal is 5. The confusion arises regarding which amplitude corresponds to the signal and which to the noise, with suggestions that the notation may contain a typo.

PREREQUISITES
  • Understanding of root mean square (RMS) calculations
  • Familiarity with Signal to Noise Ratio (SNR) concepts
  • Knowledge of logarithmic functions in signal processing
  • Basic understanding of sine wave properties
NEXT STEPS
  • Research the derivation of the RMS value for different waveforms
  • Learn about the implications of SNR in communication systems
  • Explore common signal processing errors and their resolutions
  • Study the effects of noise on signal integrity in multimedia applications
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Students in multimedia and signals courses, signal processing engineers, and anyone involved in analyzing and optimizing signal quality in noisy environments.

Whoohw
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Question one

Homework Statement


x[n] = 5sin(0.22*pi)
The root mean square (RMS) value eof a sin wave is known to be A/root(2) where A is the amplitude. If the noise in a system is known to have an RMS value of 0.5, what si the signal to noise ration (in dB) of the x[n] in this syetem.

Homework Equations


RMS = A/root(2)
SNR = (Asignal/Anoise)^2
SNRdB = 10log10(SNR)

The Attempt at a Solution


Well, i figured that "A" for the RMS given (0.5) is root(2)/2

However, i do not know that which A is Asignal and which is Anoise (root(2)/2 or 5*sin(.22*pi) or just 5).
 
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Whoohw said:
Question one

Homework Statement


x[n] = 5sin(0.22*pi)
Shouldn't the formula above have n on the right side? Otherwise, all your values of x[n] are exactly the same.
Whoohw said:
The root mean square (RMS) value eof a sin wave is known to be A/root(2) where A is the amplitude. If the noise in a system is known to have an RMS value of 0.5, what si the signal to noise ration (in dB) of the x[n] in this syetem.

Homework Equations


RMS = A/root(2)
SNR = (Asignal/Anoise)^2
SNRdB = 10log10(SNR)

The Attempt at a Solution


Well, i figured that "A" for the RMS given (0.5) is root(2)/2

However, i do not know that which A is Asignal and which is Anoise (root(2)/2 or 5*sin(.22*pi) or just 5).
 
Thats what I keep thinking, but i that isn't what the problem has in the notation.
 
Then I'd be willing to bet that it's a typo. Otherwise you don't have a sine wave. In that case x[n] is equal to about 3.1871 for all n. IOW, it's constant.
 

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