Signal to Noise Ratio: Questions for my multimedia and signals class

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Discussion Overview

The discussion revolves around a homework problem related to calculating the signal-to-noise ratio (SNR) in a multimedia and signals class. Participants are examining the formula for the root mean square (RMS) value of a sine wave and its application in determining the SNR given a specific noise level.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant states the RMS value of a sine wave is A/root(2) and questions which amplitude (A) corresponds to the signal or noise in the context of the problem.
  • Another participant points out a potential issue with the notation in the problem, suggesting that the formula should include "n" to represent varying values of x[n].
  • A later reply agrees with the notation concern, implying that without "n," the values of x[n] would be constant, specifically around 3.1871.
  • There is uncertainty regarding the correct interpretation of the problem's notation and its implications for the sine wave representation.

Areas of Agreement / Disagreement

Participants express differing views on the notation used in the problem, with some suggesting it may be a typo. The discussion remains unresolved regarding the correct interpretation of the amplitude values and their application in the SNR calculation.

Contextual Notes

There is a lack of clarity on the definitions of Asignal and Anoise, as well as the implications of the notation used in the problem statement. The discussion highlights potential ambiguities in the mathematical formulation.

Whoohw
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Question one

Homework Statement


x[n] = 5sin(0.22*pi)
The root mean square (RMS) value eof a sin wave is known to be A/root(2) where A is the amplitude. If the noise in a system is known to have an RMS value of 0.5, what si the signal to noise ration (in dB) of the x[n] in this syetem.

Homework Equations


RMS = A/root(2)
SNR = (Asignal/Anoise)^2
SNRdB = 10log10(SNR)

The Attempt at a Solution


Well, i figured that "A" for the RMS given (0.5) is root(2)/2

However, i do not know that which A is Asignal and which is Anoise (root(2)/2 or 5*sin(.22*pi) or just 5).
 
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Whoohw said:
Question one

Homework Statement


x[n] = 5sin(0.22*pi)
Shouldn't the formula above have n on the right side? Otherwise, all your values of x[n] are exactly the same.
Whoohw said:
The root mean square (RMS) value eof a sin wave is known to be A/root(2) where A is the amplitude. If the noise in a system is known to have an RMS value of 0.5, what si the signal to noise ration (in dB) of the x[n] in this syetem.

Homework Equations


RMS = A/root(2)
SNR = (Asignal/Anoise)^2
SNRdB = 10log10(SNR)

The Attempt at a Solution


Well, i figured that "A" for the RMS given (0.5) is root(2)/2

However, i do not know that which A is Asignal and which is Anoise (root(2)/2 or 5*sin(.22*pi) or just 5).
 
Thats what I keep thinking, but i that isn't what the problem has in the notation.
 
Then I'd be willing to bet that it's a typo. Otherwise you don't have a sine wave. In that case x[n] is equal to about 3.1871 for all n. IOW, it's constant.
 

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