Signal to Noise Ratio: Questions for my multimedia and signals class

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
3 replies · 3K views
Whoohw
Messages
5
Reaction score
0
Question one

Homework Statement


x[n] = 5sin(0.22*pi)
The root mean square (RMS) value eof a sin wave is known to be A/root(2) where A is the amplitude. If the noise in a system is known to have an RMS value of 0.5, what si the signal to noise ration (in dB) of the x[n] in this syetem.

Homework Equations


RMS = A/root(2)
SNR = (Asignal/Anoise)^2
SNRdB = 10log10(SNR)

The Attempt at a Solution


Well, i figured that "A" for the RMS given (0.5) is root(2)/2

However, i do not know that which A is Asignal and which is Anoise (root(2)/2 or 5*sin(.22*pi) or just 5).
 
Physics news on Phys.org
Whoohw said:
Question one

Homework Statement


x[n] = 5sin(0.22*pi)
Shouldn't the formula above have n on the right side? Otherwise, all your values of x[n] are exactly the same.
Whoohw said:
The root mean square (RMS) value eof a sin wave is known to be A/root(2) where A is the amplitude. If the noise in a system is known to have an RMS value of 0.5, what si the signal to noise ration (in dB) of the x[n] in this syetem.

Homework Equations


RMS = A/root(2)
SNR = (Asignal/Anoise)^2
SNRdB = 10log10(SNR)

The Attempt at a Solution


Well, i figured that "A" for the RMS given (0.5) is root(2)/2

However, i do not know that which A is Asignal and which is Anoise (root(2)/2 or 5*sin(.22*pi) or just 5).
 
Thats what I keep thinking, but i that isn't what the problem has in the notation.
 
Then I'd be willing to bet that it's a typo. Otherwise you don't have a sine wave. In that case x[n] is equal to about 3.1871 for all n. IOW, it's constant.