(adsbygoogle = window.adsbygoogle || []).push({}); Question one

1. The problem statement, all variables and given/known data

x[n] = 5sin(0.22*pi)

The root mean square (RMS) value eof a sin wave is known to be A/root(2) where A is the amplitude. If the noise in a system is known to have an RMS value of 0.5, what si the signal to noise ration (in dB) of the x[n] in this syetem.

2. Relevant equations

RMS = A/root(2)

SNR = (Asignal/Anoise)^2

SNRdB = 10log10(SNR)

3. The attempt at a solution

Well, i figured that "A" for the RMS given (0.5) is root(2)/2

However, i do not know that which A is Asignal and which is Anoise (root(2)/2 or 5*sin(.22*pi) or just 5).

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# Homework Help: Signal to Noise Ratio: Questions for my multimedia and signals class

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