Significance of 1/s in Root Loci & Nyquist Stability

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Discussion Overview

The discussion revolves around the significance of the transformation \( s \rightarrow \frac{1}{s} \) in the context of a closed feedback system characterized by the loop gain \( L(s) = G(s)H(s) \). Participants explore its implications for root loci and Nyquist stability, questioning the validity and physical significance of such a transformation.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • Vivek introduces the transformation and its potential mapping of points at infinity to zero, questioning its implications for root loci and Nyquist stability.
  • One participant seeks clarification on the purpose of the transformation, suggesting it may relate to the invertibility of the characteristic equation.
  • Another participant expresses uncertainty about the transformation's effect on root loci and Nyquist stability, noting that it may provide insight into high-frequency behavior.
  • A different viewpoint suggests that the understanding of points at infinity is already established, and questions whether the transformation accurately represents high-frequency regions without modifying the Laplace or Fourier transform.

Areas of Agreement / Disagreement

Participants express differing views on the transformation's significance and implications, indicating that multiple competing perspectives remain without consensus on its validity or physical meaning.

Contextual Notes

Participants highlight the need for further clarification on the transformation's impact on established concepts and the potential requirement for modifications to transforms used in analysis.

maverick280857
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Hi

Suppose we have a closed feedback system with loop gain = L(s) = G(s)H(s). The characteristic equation is

[tex]1 + L(s) = 0[/tex]

What is the significance of the transformation [itex]s \rightarrow 1/s[/itex] and what bearing does it have on root loci and Nyquist stability?

I can see that the points [itex]s = \pm \infty[/itex] will be mapped to [itex]s = 0[/itex].

Thanks,
Vivek.
 
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Anyone?
 
I don't get why you transform s to 1/s. Can you elaborate more on the question? Do you mean the invertibility of the char. eq i.e. [itex](1+L(s))^{-1}[/itex] ?
 
Last edited:
Well, the question really is: what happens to the Root Locus and the Nyquist Stability criterion when I replace s by 1/s? Are they valid? Also, what is the physical significance of such a transformation. Intuitively, I think that such a substitution allows us to map points at infinity to the origin (and conversely)...so, it allows us to get a better "idea" of the high frequency behavior. But I am not fully convinced.
 
But we have already an understanding of the points at infinity, it is completely meaningful when we take [itex]s|_{j\omega}\to\infty[/itex].

Besides that, though I am not sure, I don't think that it will map the high frequency region as such because you have to also modify the laplace or Fourier transform accordingly.
 

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