For anybody coming in new to this thread, at the moment I am chewing over the first page of what I think is the best current presentation of LQG, which is an October 2010 paper
http://arxiv.org/abs/1010.1939
Accidentally trashed much of my earlier post (#68) so will try to reconstruct using whatever remains.
In post #67 I was talking about how equation (4) implements Feynman Rule 2.
Now let's look at Rule 3 and see how it is carried out.
There's one tricky point about Rule 3--it involves elements g of a larger group SL(2 C).
This has a richer set of representation, so the characters are not simply labeled by halfintegers.
As before, what is inside the integral will be a product of group character numbers of the form χ(g) where this time g is in SL(2,C). The difference is that SL(2,C) reps are not classified by a single halfinteger j, but by a pair of numbers p,j where j is a halfinteger but p doesn't have to be a halfinteger, can be a real, like for instance the immirzi number γ = .274... multiplied by a half integer (j+1). Clearly a positive real number, not a halfinteger.
χ
γ(jf+1), jf (g)Rule 3 says to assign to each face f in the foam a certain sum ∑
jf
the sum is over all possible halfintegers j, since we are focusing on a particular face f we are going to tag that run of halfintegers j
f.
And that sum is simply a sum of group character numbers (multiplied by an integer 2j+1 which is the dimension of the vectorspace of the j-th rep). Here's the sum:
∑
jf (2j
f+1)χ
γ(jf+1), jf (g)
Now the only thing I didn't specify is what group element that generic "g" stands for, that is plugged into the character χ. Well it stands for a kind of circle-dance where you take a product of edge labels going around the face.
∏
e ∈ ∂f (g
ese h
ef g
ete-1)
εlf
And when you do that there is the question of orientation. Each edge has its own orientation given by its source and target vertex assignment. And each face has an oriention, a preferred cyclic ordering of the edges. Since edges are shared by two or more faces, you can't count on the orientations of edges being consistent. So what the epsilon exponent does is fix that. It is either 1 or -1, whatever is needed to make orientation agree.
===========================
Now looking at the first integral of equation (4),
namely ∫
(SL2C)2(E-L)-V dg
ev ,
we can explain the exponent 2(E-L)-V by referring back to Rule 1 and Rule 4 together.Rule 1 says for every internal edge you expect two integrals dg
ev
where the v stands for either the source or the target vertex of that particular edge e so g
ev stands for either
g
ese or g
ete
Well there are L boundary edges, and the total number of edges in the foam is E. So there are E-L internal edges. So Rule 1 would have you expect 2(E-L) integrations dg
ev over SL(2,C).
Rule 4 then adds the provision at each vertex one integration is redundant and is omitted.
So V being the number of vertices, that means V integrations are dropped. And we are left with
2(E-L) - V.
Intuitively what those SL(2, C) integrations are doing is working out all the possible gauge tranformations that could happen to a given SU(2) label h
ef on an edge e of a face f.αβγδεζηθικλμνξοπρσςτυφχψωΓΔΘΛΞΠΣΦΨΩ∏∑∫∂√±←↓→↑↔ ~≈≠≡ ≤≥½∞ ⇐⇑⇒⇓⇔∴∃ℝℤℕℂ⋅∈[/QUOTE]