Silly Gravity / Radius Question

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The discussion centers on determining the radius of a planet with the same mass as Earth but half its gravitational acceleration. The gravitational force equation is referenced, leading to the conclusion that to achieve half the gravitational acceleration (g/2), the radius must be increased. Specifically, the radius should be multiplied by the square root of 2 (approximately 1.414). This relationship highlights the inverse square law of gravity, where increasing the radius decreases gravitational acceleration. The final conclusion is that the radius of the planet must be about 1.414 times that of Earth's radius.
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I think this is pretty basic, but I'm obviously missing something. Here's the ?:

A planet has the same mass as earth, but it's gravitational acceleration is g/2. What is the radius of the planet?


What's the relationship here? -AT77A
 
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Well, let me see (correct me if I'm wrong)

\vec{F} = G \frac{m_{1}m_{2}}{r^2} \vec{r}

m_{2} \vec{g} = G \frac{m_{1}m_{2}}{r^2} \vec{r}

\vec{g} = G \frac{m_{1}}{r^2} \vec{r}

so, if g/2

\frac{\vec{g}}{2} = \frac{G \frac{m_{1}}{r^2}}{2} \vec{r}
 
For a constant mass, to cut g in half, you have to increase the radius by 1.414... (sqrt(2)).
 
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