Simple but tricky problem, horizontal motion

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A cannonball is fired horizontally at a speed of 956 m/s and strikes 0.2 m below the target. To solve for the horizontal distance, first calculate the time it takes for the cannonball to fall 0.2 m using the vertical displacement formula. Once the time is determined, use it to find the horizontal distance traveled by multiplying the time by the initial speed. A visual representation of the projectile's path, both with and without gravity, can aid in understanding the motion. This approach effectively breaks down the problem into manageable steps for accurate calculation.
phynoob
Im studying for my test and I have a problem from my previous notes. It should be simple but I am having some difficulty.

''
A cannon is shooting horizontally at a target. The cannonball strikes .2m below the bullseye. If the initial speed of the cannonball is 956m/s, what is the distance?
''

Any help would be appreciated.
 
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Draw a picture of what it looks like, include the path if there was no gravity and then draw the actual path. You are solving for D_y that should be plenty to get you started.
 
Find the value of t from the vertical displacement. Then find horizontal distance by using the value.
 

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