- #1
boomer22
- 6
- 0
Homework Statement
y ' [x] = xy
y[0] = 1
Homework Equations
none
The Attempt at a Solution
I posted this somewhere else and 2 people got the answer is y = e^x
I am getting something else though.
I get up to here:
dy/dx = xy
1/y dy = x dx
ln y = (x^2)/2 + C
that is what i get to, but here is what the other person got from this point:
y = e^[ (x^2/2) + C ] (Im not confused on e^ln^y = y fyi)
then he simplified that to:
y = Ce^x (I DONT understand that property of natural logs)
1 = C * e^0
C = 0
y = e^x
anyone care to explain? don't worry if you know a better way and start from scratch, ignore mine and this other guys answer if you want.