Simple equation solving (I think)

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To find the x-intercepts of the function f(x) = ln(x+1) - (sinx)^2, the equation can be simplified to ln(x+1) = (sinx)^2. It is noted that there are three x-intercepts, with x = 0 being the most apparent. Analyzing the maximum and minimum values of sin^2(x) helps establish a range of x-values where x-intercepts may exist. Graphing f(x) within this domain allows for estimation of the x-intercepts. While Newton's method can refine these estimates, it may be considered complex for a pre-calculus level.
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Homework Statement



Find x-intercepts of f(x)= ln(x+1)-(sinx)^2

I know to get to ln(x+1)=(sinx)^2 but have no idea what to do after that.
 
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I don't think it's THAT easy, x = 0 comes to mind though
 
It turns out that there are 3 x-intercepts (x=0 is the obvious one). You can estimate what domain they lie in by looking at the maximum and minimum values of \sin^2(x)...what are those? What does that tell you about the max/min of \ln(1+x) for which there might be any x-intercepts? You can use that to determine a range of x-values for which x-intercepts are possible.

The next step would be to graph f(x) over that Domain and estimate value for the x-intercepts.

If you are familiar with Newton's method, you can improve your estimations through a few iterative calculations.
 
This seems to be kind of an overkill for someone in pre-calc though unless you were allowed to use a CAS.
 
Use iteration?
 
Yes you could use Newton's as was mentioned but I still maintain it's a somewhat hard problem for pre-calc then again I never took pre-calc and maintain that it's a useless class :)
 
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