Simple Gear Train: Pitch Circle Diameter and Typo in Homework

AI Thread Summary
The discussion centers on the calculation of pitch circle diameters in gear systems, highlighting a potential typo in homework equations. The correct pitch circle diameter is calculated as 38*25/pi, yielding approximately 302.394 mm, while the second diameter should be 907.183 mm. Participants agree that the provided equation appears incorrect, as it uses an inaccurate value for pi. Additionally, there is a debate about gear ratios, noting that single-stage spur gears typically have a maximum ratio of around 10, with some suggesting it should be under 7 for practical applications. The conversation also mentions that rack and pinion systems can achieve infinite ratios, illustrating the complexity of gear design.
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Homework Statement


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Homework Equations

The Attempt at a Solution


if you do 38*25/pi , you would get 302.394 for the exact pitch circle diameter, similarly, exact d2 should be 907.183 mm, is it a typo? or did I miss something?
 

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The used a slightly different value for pi. Probably 3.142
 
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CWatters said:
The used a slightly different value for pi. Probably 3.142
the new exact d1 should be T1*Pc/pi, correct? but it has only Pc/T1
 
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You can have a single stage with a bigger ratio but I think there are frequently better options, eg a multi stage might be smaller or have less wear. I am not a mechanical engineer but I think single stage spur gears for power transmission are normally limited to somewhere under 10. Some sites say under 7. The issue is with the small gear, where I think the practical minimum number of teeth is around 20 teeth.

Technically a rack and pinion has an infinite ratio.

Some tower cranes have a small pinion turning a very large ring gear under the cab and I think the ratio there might be more than 20. That's in addition to a sealed gearbox between the electric motor and pinion.
 
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