Testing Point (5,4) in Triangle with 3 Given Points (1,2), (4,6), and (9,10)

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To determine if point (5,4) is inside the triangle formed by the vertices (1,2), (4,6), and (9,10), three inequalities based on the triangle's sides must be satisfied. The inequalities derived from the lines connecting the vertices are y <= 4/3x + 2/3, y >= x + 1, and y <= 4/5x + 14/5. The analysis shows that while the first inequality holds true, the other two do not, indicating that point (5,4) is outside the triangle. Graphing the inequalities can visually confirm the position of the point relative to the triangle. This method of using inequalities is a straightforward approach to solving the problem.
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Given 3 points of the triangle:
(1,2)
(4,6)
(9,10)
Determine if point (5,4) belongs to triangle (is located inside the triangle).

the only way i can think of doing this is as follows but there must be a more sound way.

so you have lines:
(1,2)->(4,6)
(4,6)->(9,10)
(1,2)->(9,10)

you need all 3 of the following to hold true for point (5,4)

y <= 4/3x + 2/3 (true)
y >= x + 1 (false)
y <= 4/5x + 14/5 (false)



any help greatly appreciated.
 
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If by "Given 3 points" you really mean "Given 3 vertices", then your basic approach is very good. As long as you identified the correct lines, then you can set up the suitable inequalities and determine the necessary truths for the conditions.

You can easily check about the point by actually drawing the whole graph.
 
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Yes I do mean vertices. So this is pretty much the simplest way of going about it?

Thanks.
 
forty said:
Yes I do mean vertices. So this is pretty much the simplest way of going about it?

Thanks.

Make the graph of the inequalities; this can help you to explain the proof AND to show the proof graphically. Either the point to test is within the inequalities region or it is not within the inequalities region.
 
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