A massless spring with spring constant 23.5 N/m hangs vertically. A body of mass 0.30 kg is attached to its free end and then released. Assume that the spring was unstretched before the body was released. What is the frequency of oscillation of the resulting motion, assumed to be simple harmonic? ok so f=(1/2pi)[sqroot(k/m)] cuz w=sqroot(k/m) and f=w/2pi so i have (1/2pi)[sqroot(23.5/.30)] which is 13.90.....right? and the units would be Hz right becuase w is in rad/s and that divided by rad would give cycles/s i think i am doing something wrong. please point it out to me.