Simple math problem in one dimension

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The discussion centers on a physics problem involving a particle subjected to a time-varying force, F(t)=F0(1-t/T), which decreases linearly to zero. The goal is to derive expressions for the particle's speed and distance traveled at time T, specifically v(T)=v0+a0T/2 and x(T)=v0T+a0T2/3, where a0 is the initial acceleration. The participant struggles with applying Newton's second law and the relationships between acceleration, velocity, and position to derive these equations. Suggestions emphasize using time derivatives to connect these concepts effectively. The conversation highlights the importance of correctly applying fundamental physics principles to solve the problem.
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Homework Statement


A particle of mass m is subjected to a net force F(t) given by F(t)=F0(1-t/T)i; that is F(t) equals F0 at t=0 and decreases linearly to zero in time T. The particle passes the origin x=0 with velocity v0i. Show that at the instant t=T and F(t) vanishes, the speed v and distance x traveled are given by v(T)=v0+a0T/2, and x(T)=v0T+a0T2/3, where a0=F0/m is the initial acceleration. Compare these results with Eqs (vx=v0x+axt and x=x0+v0xt+1/2axt2).


Homework Equations


I should only need those listed in the problem


The Attempt at a Solution


F=ma=F0(1-t/T)
F0=ma0
a=a0(1-t/T)
a=a0-a0t/T

v=v0+at
v=v0+(a0-a0t/T)t

When t=T, those a0's cancel each other out and you end up with zero. I've also tried starting with the other one, and taking derivatives, to no avail. I can't get the math to work out to give me those coefficients.

Help is GREATLY appreciated.
 
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So you've already written Newton's 2nd Law, that's important. But what are the time derivative relationships between acceleration, velocity, and position? Use those relationships to work backwards from Newton's 2nd Law to obtain v(t) and x(t).
 
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