Simple Newtons laws question ?

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SUMMARY

The discussion focuses on the application of Newton's second law to a particle projected vertically upward against gravity and air resistance. The correct velocity equation derived is v = (v_0 + g/k) e^{-kt} - g/k, which accounts for both gravitational force and air resistance. The user initially derived the velocity as v = v_0 e^{-kt}, neglecting the gravitational force in the differential equation. The key takeaway is the necessity of including all forces acting on the particle to accurately model its motion.

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"Simple" Newtons laws question ?

At time t = 0 a particle of unit mass is projected vertically upward with velocity v_0 against gravity, and the resistance of the air to the particle's motion is κ times its velocity.
Show that during its flight the velocity v of the particle at time t is

v = (v_0 +\frac{g}{k}) e^{-kt} - \frac{g}{k}


Now what I have done is work with Newtons 2nd law:

mx'' = -mκv
v' = -κv

solving this differential equation gives:

v=Ce^{-kt}

Now v(0) = v_0 from question so:

C=v_0

v=v_0 e^{-kt}

Now clearly I missing quite a bit of stuff, so where exactly am I going wrong ?
 
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You have left the force of gravity out of the differential equation.
 

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