In summary, the size of the universe is accurately tracked by the function u(x), which scales distances down by the cosmological constant a(x). "Dark energy" (as Lambda is sometimes excitingly called) is here treated simply as a time scale. Multiplying an ordinary time by ##\sqrt{\Lambda/3}## is equivalent to dividing it by 17.3 billion years, so to take an example, suppose your figure for the present is year 13.79 billion, then the time x-number to use is: x_{now} = \sqrt{\Lambda/3}\ 13.79\ billion\ years=
#106
Ken G
Gold Member
4,897
538
I do like cosmaeon. Perhaps a title like "How many eons in a cosmaeon?"