Using a Resistor to Power Multiple Devices: A Simple Guide

AI Thread Summary
A 12V power supply rated at 17.9A can safely power a device requiring 12V and 10.83A without needing a resistor. The lower current device will only draw the amount of current it needs from the supply. The 17.9A rating indicates the maximum current the power supply can deliver, not a constant output. It's advisable not to operate the power supply at its maximum capacity for optimal performance. Using the power supply directly for the lower current device is the simplest and most effective solution.
jaydnul
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I have a power brick (transformer) that sends 12V, 17.9A to a device. I have another device that requires 12V, 10.83A. If I put a 1.7 ohm resistor in parallel to draw some of the current:

\frac{12V}{17.90A-10.83A}=1.697312

Could I use it to power the 10.83A device? I'm just not sure if it is as simple as that.

Also, when it says 17.9A on the transformer, does that just mean that is the MAX current that can be drawn, or is that what it is always sending?

Edit: Sorry I should add that it is an external power supply, so it is outputting DC not AC.

Thanks
 
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Jd0g33 said:
I have a power brick (transformer) that sends 12V, 17.9A to a device. I have another device that requires 12V, 10.83A. If I put a 1.7 ohm resistor in parallel to draw some of the current:

12V17.90A−10.83A =1.697312 \frac{12V}{17.90A-10.83A}=1.697312

Could I use it to power the 10.83A device? I'm just not sure if it is as simple as that.

no you don't need all that

Just power the 12V 10.83 A device off the 12V 17.9A supply ... the lower current device will only draw what it needs from the 12V supply
Jd0g33 said:
Also, when it says 17.9A on the transformer, does that just mean that is the MAX current that can be drawn, or is that what it is always sending?

That's the max it can supply, and preferably you never want to push a PSU to its max
Jd0g33 said:
Edit: Sorry I should add that it is an external power supply, so it is outputting DC not AC.

yup I guessed that, tho my earlier answer wouldn't have made any differencecheers
Dave
 
Oh Ok. Thanks a bunch Dave!
 
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