- #1
mastiffcacher
- 25
- 0
Trying to make sure my calculations were correct. We were tasked to make 2 grams of NH4Cl. Our proposed method was using HCl and NH4ClOH. This was confirmed as our best way.
The way I figured it was that 2 grams of ammonium chloride was 0.037519 moles. We used 6M hydrochloric acid and 6M ammonium hydroxide for the reaction. I calculated that we needed 6.25 mL of each solution to make the 2 grams. Our results were horrible as we only made .186 g and .233 g in two different trials.
I am wondering if these amounts are correct at least theoretically. Does this reaction typically have this low of a percent yield? If it is usually this low of a yield, why might this be?
The way I figured it was that 2 grams of ammonium chloride was 0.037519 moles. We used 6M hydrochloric acid and 6M ammonium hydroxide for the reaction. I calculated that we needed 6.25 mL of each solution to make the 2 grams. Our results were horrible as we only made .186 g and .233 g in two different trials.
I am wondering if these amounts are correct at least theoretically. Does this reaction typically have this low of a percent yield? If it is usually this low of a yield, why might this be?