1. The problem statement, all variables and given/known data A ladybug with a velocity of 10.0mm/s [W] crawls on a chair that is being pulled [50deg N of W] at 40.0mm/s. What is the velocity of the ladybug, relative to the ground? 2. Relevant equations pythag theorum component vectors sohcahtoa 3. The attempt at a solution Let [N] and [W] be positive. Velocity of the ladybug relative to the chair = VLC = 10mm/s [W] Components: VLCx = 10mm/s VLCy = 0mm/s Velocity of the chair, relative to the ground = VCG = 40mm/s [W50degN] Components: VCGx = 40mm/s (cos50) = 25.71150439mm/s VCGy = 40mm/s (sin50) = 30.64177772mm/s Velocity of the ladybug, relative to the ground = VLG = ? Components: VLGx = VLCx + VCGx = 35.71150439mm/s VLGy = VLCy + VCGy = 30.64177772mm/s Direction of VLG ∅ (theta?) = tan-1(opposite/adjacent) = tan-1(VLGy / VLGx) = tan-1(30.64177772mm/s / 35.71150439mm/s) = 40.63 degrees ∴ VLG = √2214.230088 = 47.05560634mm/s [ W 40.63deg N ] I feel that my calculations are correct. However, looking up this question on the net shows that people have come to a different end result: https://www.physicsforums.com/showthread.php?t=596229 Specifically, the direction of the resultant vector is different. I just want to be sure that my answer is correct before I submit it for marking. Thanks.