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Homework Help: Simple single variable integral calc

  1. Feb 25, 2008 #1
    1. The problem statement, all variables and given/known data

    e^x dx
    1+e^2x

    2. Relevant equations



    3. The attempt at a solution

    Its the e^x and the e^2x thats tripping me up, i know that e^x is just itself but what is the rule behind e^2x?
     
  2. jcsd
  3. Feb 25, 2008 #2
    u = e^x
    du= e^xdx

    So then your integral is

    u/(1+u^2)du

    Does that look like something (think arc(something))
     
  4. Feb 25, 2008 #3
    [tex]\int\frac{e^x}{1+e^{2x}}dx[/tex]

    [tex]u=e^x[/tex]
    [tex]du=e^xdx[/tex]

    PowerIso meant ...

    [tex]\int\frac{du}{1+u^2}[/tex]
     
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