Simple single variable integral calc

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chromecarz00
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Homework Statement



∫ e^x dx
1+e^2x

Homework Equations


The Attempt at a Solution



Its the e^x and the e^2x that's tripping me up, i know that e^x is just itself but what is the rule behind e^2x?
 
u = e^x
du= e^xdx

So then your integral is

u/(1+u^2)du

Does that look like something (think arc(something))
 
[tex]\int\frac{e^x}{1+e^{2x}}dx[/tex]

[tex]u=e^x[/tex]
[tex]du=e^xdx[/tex]

PowerIso meant ...

[tex]\int\frac{du}{1+u^2}[/tex]