Simple solutions question (dilution)

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To find the final concentration of the Fe3+ solution after dilution, the formula C1*M1 = C2*M2 can be applied. The initial concentration of Fe3+ is 0.0007 mol/L, and the volume is 3 mL, which will be diluted to a final volume of 100 mL. It is important to consider the presence of SCN- and whether it is in excess, as this could affect the equilibrium and concentration of the complex formed. The final concentration will depend on the moles of the target ion after dilution and the total volume. Clarifying the final concentration of which specific ion is essential for accurate calculations.
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Homework Statement




Hi. If I have 3 mL of a Fe3+ solution (0.0007 mol/L) and that is treated with SCN- to form a complex and then is diluted until I have 100 mL of a solution.

What would be the final concentraton of that solution?

Homework Equations



C1*M1= C2*M2

The Attempt at a Solution



I Thought of the equation above, but I know that the formation of that comple must change something!
 
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Rujano said:
What would be the final concentraton of that solution?

Concentration of what? You have several ions present (I can list about a dozen, but you don't have to know about most of them).
 
How many moles of your target compound or ion? What final volume is the solution? Molarity is moles per Liter. Is thiocyanate ion added in excess of the ferric ion?
 
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