Simple spacetime interval question

AI Thread Summary
The discussion revolves around calculating the spacetime interval between two points on a spacetime plot, specifically (0,0) and (300,700). The user correctly identifies the change in time (del t) as 700 seconds and attempts to calculate the spatial distance (del r) using the Pythagorean theorem, resulting in a value of approximately 761.577 meters. There is confusion regarding the units, as the axes are in seconds, but the interval should ultimately be in meters when using the speed of light as a conversion factor. The spacetime interval is described as an invariant quantity, meaning it remains constant for all observers regardless of their relative motion. The final calculation of the interval, using c=1, yields approximately 632.455 seconds.
Eric_meyers
Messages
64
Reaction score
0

Homework Statement


on a spacetime plot (y-axis) = t (x-axis) = x find the spacetime interval between points (0,0) and (300,700)


Homework Equations


Interval = (c^2(del t)^2 - (del r)^2)^1/2


The Attempt at a Solution


So I can see clearly my del t is 700 (700 - 0 = 700 ) but for the change in r I'm sort of confused about, I'm taking r to be ((700-0)^2 + (300-0)^2)1/2 = 761.577 and thus my spacetime interval number comes out to be 2.1 * 10^11 but I'm unsure if I did the change in r correctly and I'm also not sure what the unit of this number is if it has a unit?
 
Physics news on Phys.org
The variable r is the spatial distance between the two events, so in this problem, it's equal to x.
 
The unit works out to be in meters but my axis's are both in seconds.. I don't quite understand how this can be resolved or what this interval is even telling me.
 
You're not using the regular SI units. If you did, time would be measured in seconds, and ct would be in meters, as would be r, so the interval would also be in meters. But it's often convenient to use units where c=1. In this system, time and distance have the same units, usually meters, but you seem to have converted everything to seconds. Think of c as a conversion factor. It tells you 1 second is equal to 3.0\times 10^8 meters.

The interval is essentially the distance between two points in spacetime. It's an invariant, meaning that all inertial observers will calculate the same value for the interval between two events, regardless of their relative velocities.
 
oh so my spacetime interval would then be (700^2-300^2)^1/2 = 632.455 seconds, taking c = 1

Thanks.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...

Similar threads

Back
Top