Simple Y-parameter (admittance-parameter) matrix problem?

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SUMMARY

The discussion centers on the calculation of Y-parameters in a circuit analysis context, specifically addressing the admittance-parameter matrix. The general form of the Y-parameter is defined as [I1] = [Y11 Y12][V1] and [I2] = [Y21 Y22][V2]. The solution involves calculating Y11 using the formula Y11 = (1/Ya + 1/Yb)s, where a 1V source is applied to the left side and the right side is short-circuited. The conclusion reached is that the correct answer to the problem is option A, based on the addition of individual admittance parameters for two networks.

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simple Y-parameter (admittance-parameter) matrix problem??

Homework Statement


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Homework Equations


general form of Y-parameter is
[I1]=[Y11 Y12][V1]
[I2]=[Y21 Y22][V2]

The Attempt at a Solution


i think i was confused what exactly this problem asked for. the general equation for I1 for instance you would add the variables, so I1=Y11(V1)+Y12(V2). to calculate Y11 also, you would add a 1V source on the left side, and short-circuit the right side. so I'm pretty sure it would be Y11=(\frac{1}{Ya}+\frac{1}{Yb})s. since the only signs i saw in these equations were '+' i put the 1st choice (A) as my answer.
 
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A is the answer.

The idea is that, for two networks, the input currents i1A and i11B are added and so are the output currents i2A and i2B . This implies that the individual admittance parameters yij for A and B are also added.
 

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